G(t)=3t^2-4t+5

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Solution for G(t)=3t^2-4t+5 equation: 



(G)=3G^2-4G+5

We move all terms to the left:

(G)-(3G^2-4G+5)=0

We get rid of parentheses

-3G^2+G+4G-5=0

We add all the numbers together, and all the variables

-3G^2+5G-5=0

a = -3; b = 5; c = -5;
Δ = b2-4ac
Δ = 52-4·(-3)·(-5)
Δ = -35
Delta is less than zero, so there is no solution for the equation

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